quick php "round" off question

[ckevin]

How can I round off integers so that it can have exactly 1 dec. place?

E.g. if I use PHP "round" command:

when the value is 4, the outcome is 4
the value is 4.123, the outcome is 4.1,

what I really want is value 4 --> outcome 4.0
value 4.123 --> outcome 4.1

Thanks!

 

[bigperm]

from php.net

float round ( float val [, int precision])


Returns the rounded value of val to specified precision (number of digits after the decimal point). precision can also be negative or zero (default).

So it looks like

round (4, 1) will return 4.0

 

[ckevin]

bigperm, I have tried, but the outcome is "4" only...

<? 

$row = round(4,1) ;
echo "$row" ;

?>

You can try yourself, and my php version is 4.0.6

Thanks!

Kevin

 

[hohoho]

try round(4, 2)

 

[Dusty]

Round won't do what you're trying to accomplish, use printf instead (or sprintf if you're doing something with the variable other than printing it).

printf("%.1f",$row);