Christopher
New Member
Code:
It says "Warning: shuffle() expects parameter 1 to be array, null given in..." Parameter 1 is an array!
PHP:
function random($num=5,$sep="<br><br>",$type="aff")
{
if($type == "aff")
shuffle($aff);
else
shuffle($affi);
for($i=0; $i<$num; $i++)
{
print $type[$i];
print $sep;
}
}
It says "Warning: shuffle() expects parameter 1 to be array, null given in..." Parameter 1 is an array!